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¿¹) Çб³ÀÇ ¹ß±Þ¼ö¼ö·á 500¿øÀΰæ¿ì
- °°Àº Á¾·ùÀÇ Áõ¸í¼¸¦ 2¸Å¹ß±Þ
Çб³ÀÇ ¹ß±Þ¼ö¼ö·á(1,000¿ø)+´ëÇà¼ö¼ö·á(1,500¿ø) = 2,500¿ø
[¹ß±Þ¼ö¼ö·á´Â 500¿ø¡¿2¸Å,´ëÇà¼ö¼ö·á´Â ùÀå 1,000¿ø + µÎ¹øÂ°Àå 500¿ø]
- ´Ù¸¥ Á¾·ùÀÇ Áõ¸í¼·Î °¢°¢ 1¸Å¾¿ ÃÑ 2¸Å¸¦ ¹Þ´Â °æ¿ì
Çб³ÀÇ ¹ß±Þ¼ö¼ö·á(1,000¿ø)+´ëÇà¼ö¼ö·á(2,000¿ø) = 3,000¿ø
[¹ß±Þ¼ö¼ö·á´Â 500¿ø¡¿2¸Å,´ëÇà¼ö¼ö·á´Â ùÀå 1,000¿ø ¡¿2¸Å]
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